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fix: ユーザー検索で、クエリがusernameの条件を満たす場合はusernameもLIKE検索するように (#8644) 

* Fix #8643

* 部分一致にする
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tamaina 2022-05-14 15:24:44 +09:00 committed by GitHub
parent 22bb1a1793
commit b2a5076d14
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1 changed files with 8 additions and 1 deletions
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9
packages/backend/src/server/api/endpoints/users/search.ts
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@ -61,7 +61,14 @@ export default define(meta, paramDef, async (ps, me) => {
.getMany(); .getMany();
} else { } else {
const nameQuery = Users.createQueryBuilder('user') const nameQuery = Users.createQueryBuilder('user')
.where('user.name ILIKE :query', { query: '%' + ps.query + '%' }) .where(new Brackets(qb => {
qb.where('user.name ILIKE :query', { query: '%' + ps.query + '%' });
// Also search username if it qualifies as username
if (Users.validateLocalUsername(ps.query)) {
qb.orWhere('user.usernameLower LIKE :username', { username: '%' + ps.query.toLowerCase() + '%' });
}
}))
.andWhere(new Brackets(qb => { qb .andWhere(new Brackets(qb => { qb
.where('user.updatedAt IS NULL') .where('user.updatedAt IS NULL')
.orWhere('user.updatedAt > :activeThreshold', { activeThreshold: activeThreshold }); .orWhere('user.updatedAt > :activeThreshold', { activeThreshold: activeThreshold });